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JEE MAIN - Mathematics (2021 - 18th March Morning Shift - No. 18)

The missing value in the following figure is

JEE Main 2021 (Online) 18th March Morning Shift Mathematics - Permutations and Combinations Question 117 English
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4

Explicació

Inside number $=\left(\right.$ difference)${ }^{(\text {difference}) !}$

$=($Greater number - Smaller number)(Greater number - Smaller number)!

i.e. $1=(2-1)^{(2-1) !}, $

$4^{24}=(12-8)^{(12-8) !}, $

$3^6=(7-4)^{(7-4) !}$

$\therefore \quad ?=(5-3)^{(5-3) !}$

$\therefore$ Required number $=2^{2 !}=2^{2 \times 1}=4$

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